Answer:
[tex]N_1 = 8.75 \times 10^5 [/tex]
Explanation:
Net charge on amoeba is given as
[tex]Q = 0.300 pC[/tex]
also we know that
[tex]1 pC = 10^{-12}C[/tex]
now we know that
[tex]Q = 0.300 \times 10^{-12} C[/tex]
here we know by the quantization of charge
[tex]Q = (N + N_1)e[/tex]
[tex]0.3 \times 10^{-12} = ((1.00 \times 10^6) + N_1)(1.6 \times 10^{-19})[/tex]
now we have
[tex]1.87 \times 10^6 = 1.00 \times 10^6 + N_1[/tex]
[tex]N_1 = 8.75 \times 10^5 [/tex]