First, let's write the problem. [tex]9\le \:17-4x[/tex] We are going to switch sides in order to have the x on the left side. [tex]17-4x\ge \:9[/tex] Subtract 17 from both sides. [tex]17-4x-17\ge \:9-17[/tex] [tex]-4x\ge \:-8[/tex] We have two options, divide both sides by -4, or multiply both sides by -1 in order to reverse the inequality. Let's try the second option. [tex]\left(-4x\right)\left(-1\right)\le\left(-8\right)\left(-1\right)[/tex] [tex]4x\le \:8[/tex] Divide both sides by 4. [tex]\frac{4x}{4}\le \frac{8}{4}[/tex]
Our final answer would be, [tex]x\le \:2[/tex]
You can feel free to let me know if you have any questions regarding this! Thanks!
