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ā€¼ļøcan someone help meā€¼ļø


ā€¢ What are the other two ways that you can rewrite the
formula F=ma?
ā€¢ If I push a wheelbarrow, with a force of 240 N, with an
acceleration of 4 m/s2, how much mass does the
wheelbarrow have? (Solve using formula F=ma)

Respuesta :

Answer:

Part A:

The other two ways we can rewrite F = mĀ·a are;

1) F = dp/dt

2) F = m Ɨ d(v)/dt

Part B:

The mass of the wheelbarrow is 60 kg

Explanation:

Part A:

The other two ways of rewriting the equation are;

1) Force as the rate of change of momentum, F = dp/dt = d(mĀ·v)/dt and

2) From the above equation, where, m is constant, we have;

F = d(mĀ·v)/dt Ā = m Ɨ d(v)/dt

āˆ“ F = m Ɨ d(v)/dt

Part B:

The force with which we push the wheelbarrow = 240 N

The acceleration, a, given to the wheelbarrow (by the applied force) = 4 m/sĀ²

From F = m Ɨ a

Where;

m = The mass of the wheelbarrow

m = F/a = 240 N/(4 m/sĀ²) = 60 kg

The mass of the wheelbarrow = m = 60 kg.

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