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he magnetic coils of a tokamak fusion reactor are in the shape of a toroid having an inner radius of 0.700 m and an outer radius of 1.30 m. The toroid has 890 turns of large-diameter wire, each of which carries a current of 17.0 kA. (a) Find the magnitude of the magnetic field inside the toroid along the inner radius.

Respuesta :

Answer:

B = 4.323 T

Explanation:

We are given;

Inner radius; r_i = 0.7 m

Number of turns; N = 890 turns

Current; I = 17 KA = 17000 A

Formula for the magnetic field inside the toroid along the inner radius is given by;

B = (ÎĽ_o Ă— N Ă— I)/(2Ď€r)

ÎĽ_o is vacuum of permeability with a constant value of 4Ď€ Ă— 10^(-7) H/m

Plugging in the relevant values, we have;

B = (4π × 10^(-7) × 890 × 17000)/(2 × π × 0.7)

B = (2 Ă— 10^(-7) Ă— 890 Ă— 17000)/(0.7)

B = 4.323 T

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