(x+6)(x+3) = x²+6x+3x+18
What’s the proof here ?

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mirandar58 mirandar58

03-10-2020
Mathematics

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(x+6)(x+3) = x²+6x+3x+18
What’s the proof here ?

Respuesta :

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What value of x makes the equation true ? 4(2x-4)=16

All of the following expressions have a value between 0 and 1, excepta. \frac{(-3^{7})}{(-3)^9}b. 4^{-10}× 4^{6}c. \frac{(8^3)^3}{8^{-4}} d. ( \frac{2}{5} ^{8})

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What value of x makes the equation true ? 4(2x-4)=16

find the circumference of a circle whose radius is 15.4cm

eafinke2005 eafinke2005 · Answer 1 · 2020-10-03T17:10:19+02:00

eafinke2005 eafinke2005

03-10-2020

all real numbers

distribute (x+6)(x+3) to get x^2+6x+3x+18

your equation now looks like this:

x^2+6x+3x+18= x^2+6x+3x+18

because the equations are equal, the answer is all real numbers

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(x+6)(x+3) = x²+6x+3x+18 What’s the proof here ?

Respuesta :

Otras preguntas

(x+6)(x+3) = x²+6x+3x+18
What’s the proof here ?