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Drag the tiles to the boxes to form correct pairs. Not all tiles will be used. The height (in feet) of a rocket launched from the ground is given by the function f(t) = -16t2 + 160t. Match each value of time elapsed (in seconds) after the rocket’s launch to the rocket's corresponding instantaneous velocity (in feet/second).

Drag the tiles to the boxes to form correct pairs Not all tiles will be used The height in feet of a rocket launched from the ground is given by the function ft class=

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Answer:

The pairs are;

t,         v

2,       96

4,       32

5,       0

6,      -32

7,      -64

9,     -128

Step-by-step explanation:

The given equation is f(t) = -16·t² + 160·t

We have, the velocity, v = d(f(t))/dt = d(-16·t² + 160·t)/dt = -32·t + 160

Which gives;

t,                                 v  

0,    -32×(0) + 160 =   160

1,     -32×(1) + 160 =    128

2,    -32×(2) + 160 =    96

3,    -32×(3) + 160 =    64

4,    -32×(4) + 160 =     32

5,    -32×(5) + 160 =     0

6,    -32×(6) + 160 =   -32

7,    -32×(7) + 160 =    -64

8,    -32×(8) + 160 =    -96

9,    -32×(9) + 160 =   -128

The given velocity values are;

96, -64, 32, 0, -128, -32  which correspond to 2, 7, 4, 5, 9, 6

The pairs are;

t,         v

2,       96

4,       32

5,       0

6,      -32

7,      -64

9,     -128

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