Answer
given,
lā = 50 mm
dā = 13.1 mm
lā = 53.7 mm
dā = 12.6 mm
Area of cross section
[tex]A = \dfrac{\pi}{4}d_0^2[/tex]
[tex]A = \dfrac{\pi}{4} \times 13.1^2[/tex]
A = 134. 782 mmĀ²
The strain is
[tex]\epsilon = \dfrac{l_f-l_0}{l_0}[/tex]
Ā Ā Ā Ā Ā Ā Ā [tex]= \dfrac{53.7-50}{50}[/tex]
Ā Ā Ā Ā Ā Ā Ā = 0.074
the tensile modulus of A356 aluminium is
E = 72.4 GPa
The stress is
Ļ = ĪµE
Ā = 72.4 Ć 10ā¹ Ć 0.074
Ā = 5357.6 Ć 10ā¶ Pa
Ļ = 5357.6 MPa
[tex]UTS = \dfrac{ultimate\ load}{cross\ sectional\ area}[/tex]
[tex]UTS = \dfrac{ultimate\ load}{134.782}[/tex]
