[tex]2^{5x}=6\Rightarrow\log_22^{5x}=\log_26\qquad\text{use}\ \log_ab^n=n\log_ab\\\\5x\log_22=\log_26\qquad\text{use}\ \log_aa=1\\\\5x=\log_26\qquad\text{divide both sides by 5}\\\\x=\dfrac{\log_26}{5}\\\\\log_26\approx2.585\\\\x\approx\dfrac{2.585}{5}\to\boxed{x\approx0.52}[/tex]
